The kinetic energy of translation of 20, gm of oxygen at 47°C is (molecular wt. of oxygen is 32 ,gm/mol and R = 8.3, J/mol/K)

Q: The kinetic energy of translation of $20\, gm$ of oxygen at $47°C$ is (molecular wt. of oxygen is $32 \,gm/mol$ and $R = 8.3\, J/mol/K)$

a given data: Mass of oxygen, $m=20 gm$ No. of moles, $n=\frac{m}{M}=\frac{m}{\text { molar mass }}$ $\therefore n=\frac{20}{32}$ Temperature, $T=47^{\circ} C =320 K$ The kinetic energy of $0_{2}, E=\frac{3}{2} n R T$ $E=\frac{3}{2} \times\left(\frac{20}{32}\right) \times(8.3) \times(320)$ $E=2490 \; J$ the kintic energy of $0_{2}$ is $2490 \; J$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

The kinetic energy of translation of $20\, gm$ of oxygen at $47°C$ is (molecular wt. of oxygen is $32 \,gm/mol$ and $R = 8.3\, J/mol/K)$

A$2490 \,joules$
B$2490 \,ergs$
C$830 \,joules$
D$124.5\, joules$

Medium

STD 11 Science
JEE
STD 11 - 12 . kinetic theory of gases
Physics

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