The length of a wire of a potentiometer is $100\, cm$, and the $emf$ of its standard cell is $E\,volt$. It is employed to measure the $e.m.f$ of a battery whose internal resistance is $0.5 \,\Omega$. If the balance point is obtained at $l = 30\, cm$ from the positive end, the $e.m.f.$ of the battery is

where $i$ is the current in the potentiometer

  • A$\frac{{30E}}{{100}}$
  • B$\frac{{30E}}{{100.5}}$
  • C$\frac{{30E}}{{(100 - 0.5)}}$
  • D$\frac{{30(E - 0.5i)}}{{100}}$, 
AIEEE 2003, Medium
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