The magnetic moment of a current $(i)$ carrying circular coil of radius $(r)$ and number of turns $(n)$ varies as
AIIMS 2004, Easy
Download our app for free and get started
(d) $M = niA = ni\left( {\pi {r^2}} \right) \Rightarrow M \propto {r^2}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Two long and parallel wires are at a distance of $0.1\, m$ and a current of $5\, A$ is flowing in each of these wires. The force per unit length due to these wires will beView Solution
- 2A wire $X$ of length $50\; cm$ carrying a current of $2\,A$ is placed parallel to a long wire $Y$ of length $5\,m$. The wire $Y$ carries a current of $3\,A$. The distance between two wires is $5\,cm$ and currents flow in the same direction. The force acting on the wire $Y$ is.View Solution
- 3View SolutionBy ammeter, which of the following can be measured
- 4A uniform current carrying ring of mass $m$ and radius $R$ is connected by a massless string as shown. A uniform magnetic field $B_0$ exist in the region to keep the ring in horizontal position, then the current in the ring is ($l =$ length of string)View Solution
- 5The flux density obtained at the centre of a circular coil of radius $R$ which carries a current $i$, is $B_0$. At a distance $‘pR’$ from the centre on the axis, the flux density will beView Solution
- 6An arc of a circle of radius $R$ subtends an angle $\frac{\pi }{2}$ at the centre. It carries a current $i$. The magnetic field at the centre will beView Solution
- 7A single turn current loop in the shape of a right angle triangle with sides $5\,cm , 12\,cm , 13\,cm$ is carrying a current of $2\,A$. The loop is in a uniform magnetic field of magnitude $0.75\,T$ whose direction is parallel to the current in the $13\,cm$ side of the loop. The magnitude of the magnetic force on the $5\,cm$ side will be $\frac{ x }{130}\,N$. The value of $x$ is $..........$View Solution
- 8A charge $q$ is spread uniformly over an insulated loop of radius $r$ . If it is rotated with an angular velocity $\omega $ with respect to normal axis then the magnetic moment of the loop isView Solution
- 9Statement $-1$ : Ampere law can be used to find magnetic field due to finite length of a straight current carrying wire.View Solution
Statement $-2$ : The magnetic field due to finite length of a straight current carrying wire is symmetric about the wire.
- 10View SolutionWhich of the field patterns given below is valid for electric field as well as for magnetic field?