A condenser of capacitance $10\,\mu F$ has been charged to $100\,volts$. It is now connected to another uncharged condenser in parallel. The common potential becomes $40\,volts$. The capacitance of another condenser is......$\mu F$
Medium
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(a) By using $V = \frac{{{C_1}{V_1} + {C_2}{V_2}}}{{{C_1} + {C_2}}}$
$==>$ $40 = \frac{{10 \times 100 + {C_2} \times 0}}{{10 + {C_2}}}$ $==>$ ${C_2} = 15\,\mu F$
$==>$ $40 = \frac{{10 \times 100 + {C_2} \times 0}}{{10 + {C_2}}}$ $==>$ ${C_2} = 15\,\mu F$
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