The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is
JEE MAIN 2016, Medium
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Efficiency of heat engine is given by
$\eta = \frac{W}{Q} = 1 - \frac{{{C_V}}}{{{C_P}}} = \frac{R}{{{C_P}}} = \frac{R}{{\frac{{5R}}{2}}} = \frac{2}{5}$
$\left( {{C_P} - {C_V} = R} \right)$
For monoatomic gas ${C_P} = \frac{5}{2}R.$
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