The temperature of sink of Carnot engine is ${27^o}C$. Efficiency of engine is $25\%.$ Then temperature of source is ...... $^oC$
Medium
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(c) $\eta = 1 - \frac{{{T_2}}}{{{T_1}}}$ ==> $\frac{{25}}{{100}} = 1 - \frac{{300}}{{{T_1}}}$ ==> $\frac{1}{4} = 1 - \frac{{300}}{{{T_1}}}$
${T_1} = 400\,K = 127^\circ C$
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