MCQ
The velocity-time graph for one-dimensional motion of a particle is as shown in the figure. The acceleration of the particle is (in $m / s ^2$ ):
- ✓
- B
- Czero
- D
✓
Answer
Correct option: A.
(a) Acceleration $a=\frac{ dv }{ dt }=\tan \theta$
Here, $\theta$ is the angle made with the x axis.
$\begin{array}{ll}
\therefore \quad & \theta=90^{\circ}-30^{\circ}=60^{\circ} \\
& a=\tan 60^{\circ}=\sqrt{3}
\end{array}$
Hence, the correct option is (a).
Here, $\theta$ is the angle made with the x axis.
$\begin{array}{ll}
\therefore \quad & \theta=90^{\circ}-30^{\circ}=60^{\circ} \\
& a=\tan 60^{\circ}=\sqrt{3}
\end{array}$
Hence, the correct option is (a).
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