The volume of an ideal gas is $1$ litre and its pressure is equal to $72cm$ of mercury column. The volume of gas is made $900\, cm^3$ by compressing it isothermally. The stress of the gas will be ...... $cm$ (mercury)
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(a)For isothermal process ${P_1}{V_1} = {P_2}{V_2}$
==> ${P_2} = \frac{{{P_1}{V_1}}}{{{V_2}}} = \frac{{72 \times 1000}}{{900}}=80 \,cm$
Stress $\Delta P = {P_2} - {P_1} = 80 - 72 = 8cm$
==> ${P_2} = \frac{{{P_1}{V_1}}}{{{V_2}}} = \frac{{72 \times 1000}}{{900}}=80 \,cm$
Stress $\Delta P = {P_2} - {P_1} = 80 - 72 = 8cm$
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