Three liquids of equal masses are taken in three identical cubical vessels $A, B$ and $C .$ Their densities are $\rho_{A}, \rho_{B}$ and $\rho_{C} \cdot$ The force exerted by the liquid on the base of the cubical vessel is
AIIMS 2019, Medium
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The formula for the pressure exerted by the liquid on the base is,
$P=\rho g h$
Rewrite the above equation.
$P=\left(\frac{m}{V}\right) g h$
$P=\left(\frac{m}{A \times h}\right) g h$
$P=\frac{g m}{A}$
The force exerted by the liquid is,
$F=P \times A$
$F=\left(\frac{g m}{A}\right) \times A$
$F=g m$
since the mass of the $A, B$ and $C$ are equal.
Therefore, $F_{A}=F_{B}=F_{C}$
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