Three masses $700g, 500g$ and $400g$ are suspended at the end of a spring a shown and are in equilibrium. When the $700g$ mass is removed, the system oscillates with a period of $3\,seconds$, when the $500g$ mass is also removed, it will oscillate with a period of .... $s$
Medium
Download our app for free and get started
$\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{R}}}$
$\frac{3=2 \pi \sqrt{\frac{0.9}{\mathrm{k}}}}{\mathrm{T}=2 \pi \sqrt{\frac{0.4}{\mathrm{k}}}}$
$\mathrm{T}=2 \mathrm{sec}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionThe acceleration of a particle in S.H.M. is
- 2What is the maximum acceleration of the particle doing the $SHM$ $y = 2\sin \left[ {\frac{{\pi t}}{2} + \phi } \right]$ where $2$ is in $cm$View Solution
- 3A simple pendulum consisting of a ball of mass $m$ tied to a thread of length $l$ is made to swing on a circular arc of angle $\theta $ in a vertical plane. At the end of this arc, another ball of mass $m$ is placed at rest. The momentum transferred to this ball at rest by the swinging ball isView Solution
- 4The displacement of a particle undergoing $SHM$ of time period $T$ is given by $x(t) = x_m\,cos\, (\omega t + \phi )$. The particle is at $x = -x_m$ at time $t = 0$. The particle is at $x = + x_m$ whenView Solution
- 5View SolutionIn a simple harmonic oscillator, at the mean position
- 6Match $List - I$ with $List - II$View Solution
Choose the correct answer from the options given below
- 7A mass m oscillates with simple harmonic motion with frequency $f = \frac{\omega }{{2\pi }}$ and amplitude A on a spring with constant $K$ , thereforeView Solution
- 8View SolutionIn case of a simple pendulum, time period versus length is depicted by
- 9View SolutionA system is oscillating with undamped simple harmonic motion. Then the
- 10The displacement of a particle executing $S.H.M.$ is given by $x=0.01 \sin 100 \pi(t+0.05)$. The time period is ........ $s$View Solution