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Two capacitances of capacity ${C_1}$ and ${C_2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across ${C_1}$ will be
  • A$V\frac{{{C_2}}}{{{C_1}}}$
  • B$V\frac{{{C_1} + {C_2}}}{{{C_1}}}$
  • C$V\frac{{{C_2}}}{{{C_1} + {C_2}}}$
  • D$V\frac{{{C_1}}}{{{C_1} + {C_2}}}$
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