Two vibrating tuning forks produce progressive waves given by ${Y_1} = 4\sin 500\pi t$ and ${Y_2} = 2\sin 506\pi t.$ Number of beats produced per minute is
AIPMT 2005, Medium
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(b)From the given equations of progressive waves ${\omega _1} = 500\pi $ and ${\omega _2} = 506\pi $ ${n_1} = 250$ and ${n_2} = 253$
So beat frequency $ = {n_2} - {n_1} = 253 - 250 = 3$ beats per sec Number of beats per min = 180.
So beat frequency $ = {n_2} - {n_1} = 253 - 250 = 3$ beats per sec Number of beats per min = 180.
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