Diameter of the heel, \(d=1 cm =0.01 m\) Radius of the heel, \(r=d / 2=0.005 m\)

Area of the heel \(=\pi r^{2}=\pi(0.005)^{2}=7.85 \times 10^{-5} m ^{2}\)

Force exerted by the heel on the floor:

\(F=m g=50 \times 9.8=490 N\)

Pressure exerted by the heel on the floor:

\(P=\frac{\text { Force }}{\text { Area }}=\frac{490}{7.85 \times 10^{-5}}\)

\(=6.24 \times 10^{6} \;N m ^{-2}\)

Therefore, the pressure exerted by the heel on the horizontal floor is \(6.24 \times 10^{6} \,Nm ^{-2}\)