When the vessel is suddenly stopped then total kinetic energy will increase the temperature of the gas. Hence
\(\frac{1}{2}m{v^2} = \mu \,{C_v}\Delta T\)\( = \frac{m}{M}{C_v}\Delta T\) [As \({C_v} = \frac{R}{{\gamma - 1}}\)]
==>\(\frac{m}{M}\frac{R}{{\gamma - 1}}\Delta T = \frac{1}{2}m{v^2}\) ==> \(\Delta T = \frac{{M{v^2}(\gamma - 1)}}{{2R}}\).
કારણ : વાયુની ઝડપ માટે મેક્સવેલ ગ્રાફ સમમિતિ ધરાવે છે.