c
(c) For correcting myopia, concave lens is used and for lens.
\(u =\) wants to see \( = - \,50\,cm\)
\(v =\) can see \( = - \,25\,cm\)
From \(\frac{1}{f} = \frac{1}{v} - \frac{1}{u}\)\( \Rightarrow \frac{1}{f} = \frac{1}{{ - 25}} - \frac{1}{{( - 50)}}\)\( \Rightarrow f = - \,50\,cm\)
So power \(P = \frac{{100}}{f} = \frac{{100}}{{ - 50}} = - \,2\,D\)