When a block of mass $M$ is suspended by a long wire of length $L$, the length of the wire become $(L+l) .$ The elastic potential energy stoped in the extended wire is :
  • A$Mgl$
  • B$MgL$
  • C$\frac{1}{2} Mgl$
  • D$\frac{1}{2} \mathrm{MgL}$
NEET 2019, Easy
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