When a block of mass $M$ is suspended by a long wire of length $L$, the length of the wire become $(L+l) .$ The elastic potential energy stoped in the extended wire is :
A$Mgl$
B$MgL$
C$\frac{1}{2} Mgl$
D$\frac{1}{2} \mathrm{MgL}$
NEET 2019, Easy
Download our app for free and get started
C$\frac{1}{2} Mgl$
c $\mathrm{U}=\frac{1}{2}$ (force) (elongation)
$=\frac{1}{2}(M g) \ell=\frac{1}{2} M g \ell$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
The breaking stress of aluminium is $7.5 \times 10^7 \,Nm ^{-2}$. The greatest length of aluminium wire that can hang vertically without breaking is $......... \times 10^3 \,m ($Density of aluminium is $2.7 \times 10^3 \,kg m ^{-3} )$
$Assertion :$ Solids are least compressible and gases are most compressible.
$Reason :$ solids have definite shape and volume but gases do not have either definite shape or definite volume.
The Young's modulus of the material of a wire is $6 \times {10^{12}}\,N/{m^2}$ and there is no transverse strain in it, then its modulus of rigidity will be
A glass slab is subjected to a pressure of $10\, atm$. The fractional change in its volume is (Bulk modulus of glass $= 37 \times 10^9\, N\, m^{-2}$, $1\, atm = 1 \times 10^5\, N\, m^{-2}$)
The length of a wire is $1.0\, m$ and the area of cross-section is $1.0 \times {10^{ - 2}}\,c{m^2}$. If the work done for increase in length by $0.2\, cm$ is $0.4\, joule$, then Young's modulus of the material of the wire is
An aluminium rod with Young's modulus $Y =7.0$ $\times 10^{10} N / m ^2$ undergoes elastic strain of $0.04 \%$. The energy per unit volume stored in the rod in SI unit is:
The ratio of diameters of two wires of same material is $n : 1$. The length of wires are $4\, m$ each. On applying the same load, the increase in length of thin wire will be