When a system is taken from state $i$ to state $f$ along the path $iaf$, it is found that $Q=50$ $cal$ and $W=20$ $cal$ Along the path $ibf\ Q = 36\ cal. \ W$ along the path $ibf$ is .......  $ cal$
AIEEE 2007, Medium
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For path iaf,$\Delta U = Q - W = 50 - 20 = 30\,cal.$

For path ibf $W = Q - \Delta U = 36 - 30 = 6\,cal.$

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