$(\lambda=600 \mathrm{~nm}, d=1.0 \mathrm{~mm}, \mathrm{D}=1.0 \mathrm{~m}$ આપેલ છે.)
\(\frac{\mathrm{I}_0}{4}=\cos ^2\left(\frac{\Delta \phi}{2}\right)\)
\(\Delta \phi=\frac{2 \pi}{3}\)
\(\frac{2 \pi}{\lambda}\left(\frac{\mathrm{yd}}{\mathrm{D}}\right)=\frac{2 \pi}{3}\)
\(\mathrm{y}=\frac{\lambda \mathrm{D}}{3 \mathrm{~d}}=\frac{600 \times 10^{-9} \times 1}{3 \times 10^{-3}}=2 \times 10^{-4} \mathrm{~m}\)