$\Delta T_b = 0.18^o$ સે
$\frac{{\Delta {T_b}}}{{\Delta {T_f}}} = \frac{{{K_b} \times m}}{{{K_f} \times m}}$
$\therefore \Delta {T_f} = \frac{{{K_b} \times \Delta {T_b}}}{{{K_b}}} = \frac{{0.18 \times 1.86}}{{0.512}}$ $\therefore \text{ }\Delta {{\text{T}}_{\text{f}}}\text{ = 0}\text{.65}{{\text{4}}^{o}}$ સે
ઠારબિંદુ $\text{ = 0 - }\Delta {{\text{T}}_{\text{f}}}\,\text{=}\,\text{0 - 0}\text{.654 = - 0}\text{.65}{{\text{4}}^{o}}$ સે
($CHCl_3$ નુ મોલર દળ $= 35.5\, g\, mol^{-1}$ )
(પાણી માટે મોલલ અવનયન અચળાંક $1.80\,K\,kg\,mol ^{-1}$ અને $KCl$ નું મોલર દળ $74.6\,g\,mol ^{-1}$ છે.)
$A.$ $0.500\,M\,C _2 H _5 OH ( aq )$ અને $0.25\, M\, KBr ( aq )$
$B.$ $0.100\,M\,K _4\left[ Fe ( CN )_6\right]$ (aq) અને $0.100\, M$ $FeSO _4\left( NH _4\right)_2 SO _4$ (aq)
$C.$ $0.05 \,M\, K _4\left[ Fe ( CN )_6\right]( aq )$ અને $0.25\, M\, NaCl$ (aq)
$D.$ $0.15\, M\, NaCl ( aq )$ અને $0.1\, M BaCl _2$ (aq)
$E.$ $0.02\, M\, KCl\, MgCl _{2 .} 6 H _2 O ( aq )$ અને $0.05\, M$ $KCl ( aq )$