Questions · Page 2 of 3

1 Marks Question

Question 511 Mark
Which of the following does not react with oxygen directly?
Zn, Ti, Pt, Fe.
Answer
Pt is a noble metal and does not react very easily. All other elements, Zn, Ti, Fe, are quite reactive. Hence, oxygen does not react with platinum (Pt) directly.
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Question 521 Mark
Sulphur disappears when boiled with sodium sulphite. Why?
Answer
When sodium sulphite is heated with sulphur, we get sodium thiosulphate which is soluble in water that is why sulphur disappears.
$\text{Na}_2\text{SO}_3+\text{S}\xrightarrow{\ \ \text{Heat}\ \ }\text{Na}_2\text{S}_2\text{O}_3$
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Question 531 Mark
Why is $BiH_3$ the strongest reducing agent amongst all the hydrides of Group 15 elements?
Answer
This is because as we move down the group, the size increases, as a result, length of E-H bond increases and its strength decreases, so that the bond can be broken easily to release $H_2$ gas. Hence, $BiH_3$ is the strongest reducing agent.
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Question 541 Mark
Complete the following reactions:
  1. $C_2H_4 + O_2 →$
  2. $4Al + 3O_2 →$
Answer
  1. $\text{C}_2\text{H}_4+3\text{O}_2\xrightarrow[]{\text{Heat}}2\text{CO}_2+2\text{H}_2\text{O}$
  2. $4\text{Al}+3\text{O}_2\xrightarrow[]{\text{Heat}}2\text{CO}_2+2\text{Al}_2\text{O}_3$
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Question 551 Mark
$\text{BH}^-_4$ and $\text{NH}^+_4$ are isolobal. Explain.
Answer
Both $\text{BH}^-_4$ and $\text{NH}^+_4$ have tetrahedral shapes, i.e., four lobes of $sp^3-$ hydridised orbitals. Hence, they are isolobal.
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Question 561 Mark
Give reason for the following:
Solid phosphorus pentachloride exhibits some ionic character.
Answer
Solid $PCl_5$ exists as $[PCl_4]^+ [PCl_6]^- $ and hence exhibits some ionic character.
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Question 571 Mark
Comment on the nature of two S–O bonds formed in $SO_2$ molecule. Are the two S–O bonds in this molecule equal?
Answer
Both the S-O bonds are covalent and have equal strength due to resonating structures.
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Question 581 Mark
Why are the elements of Group 18 known as noble gases?
Answer
The elements present in Group 18 have their valence shell orbitals completely filled and, therefore, react with a few elements only under certain conditions. Therefore, they are known as noble gases.
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Question 591 Mark
Why is $F_2O$ referred to as a fluoride but $Cl_2O$ is an oxide?
Answer
$F_2O$ is called oxygen fluoride because fluorine is more electronegative than oxygen whereas $Cl_2O$ is called chlorine oxide because oxygen is more electronegative than chlorine.
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Question 601 Mark
Arrange the following in the order of property indicated for each set:
HF, HCl, HBr, HI - increasing acid strength.
Answer
In the order of increasing acid strength in water (i.e., aqueous solution) HI is strongest acid while HF is the weakest acid.
This is because as moving down the group size increase and hence weaken the bond as a result more availability of hydrogen.
H - F < H - Cl < H - Br < H - I
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Question 611 Mark
Which of the following hyride has the largest bond angle?
$H_2O, H_2S, H_2Se$ or $H_2Te$
Answer
As the electronegativity of the central atom decreases, the repulsions between element-hydrogen bond pairs decreases and hence the angle decreases accordingly. Thus, $H_2O$ has the largest bond angle $(104.5^\circ).$
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Question 621 Mark
Iodine form $\text{I}^-_3$ but $\text{F}_2$ does not form $\text{F}^-_3$ ions. Why?
Answer
$I_2,$ because of the presenve of vacant d-orbitals, accepts electrons from $I^-$ ions to from $\text{I}^-_3$ ions but $F_2$ because of the absence of d-orbitals does not accept electrons from $F^-$ ions to from $\text{F}^-_3$ ions.
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Question 631 Mark
Write two uses of $ClO_2.$
Answer
  1. $ClO_2$ is an excellent bleaching agent. It is 30 times stronger bleaching agent then the $Cl_2.$ It is used as a bleaching agerit for paper pulp in paper industry and in textile industry.
  2. Cl02 is also a powerful oxidising agent and chlorinating agent. It acts as a germicide for disinfecting water. It is used for purifying drinking water.
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Question 641 Mark
What happens when $H_3PO_3$ is heated?
Answer
$H_3PO_3,$ on heating, undergoes disproportionation reaction to form $PH_3$ and $H_3PO_4$. The oxidation numbers of P in $H_3PO_3, PH_3,$ and $H_3PO_4$ are $+3, −3,$ and +5 respectively. As the oxidation number of the same element is decreasing and increasing during a particular reaction, the reaction is a disproportionation reaction.
$H_3PO_3$ on heating disproportionates to give orthophosphoric acid and phosphine.
$4H_3 PO_3→ 3H_3PO_4 + PH_3$​​​​​​​
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Question 651 Mark
Account for the following:
Compounds of fluorine with oxygen are called fluorides of oxygen and not the oxides of fluorine.
Answer
This is because fluorine is more electronegative than oxygen.
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Question 661 Mark
List the important sources of sulphur.
Answer
Sulphur mainly exists in combined form in the earth’s crust primarily as sulphates [gypsum $(CaSO_4.2H_2O),$ Epsom salt $(MgSO_4.7H_2O),$ baryte $(BaSO_4)]$ and sulphides [(galena (PbS), zinc blends (ZnS), copper pyrites $(CuFeS_2)].$
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Question 671 Mark
How is nitrogen prepared in the laboratory? Write the chemical equations of the reactions involved.
Answer
Nitrogen is prepared by treating an aqueous solution of ammonium chloride with sodium nitrite.
$NH_4Cl(aq) + NaNO_2(aq) → N_2(g) + 2H_2O(l) + NaCl(aq)$
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Question 681 Mark
Write the structure of pyrophosphoric acid.
Answer
$\ \ \ \ \ \ \ \ \ \ \ \text{O}\ \ \ \ \ \ \ \ \ \ \ \ \text{O}\\\ \ \ \ \ \ \ \ \ \ \ || \ \ \ \ \ \ \ \ \ \ \ \ \ \ ||\\\text{HO}-\text{P}-\text{O}-\text{P}-\text{OH}\\\ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \text{OH}\ \ \ \ \ \ \ \ \ \ \text{OH}$Pyrophosphoric acid
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Question 691 Mark
Why are the Group 16 elements called chalcogens?
Answer
Chalcogens means ore forming. The elements of Group 16 are called chalcogens because many metals are found as oxides and sulphides and a few such as selenides and tellurides.
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Question 701 Mark
What are the oxidation states of phosphorus in the following:
$H_3PO_3$​​​​​​​
Answer
Oxidation can be calculated as:
$H_3PO_3$​​​​​​​
oxidation state of hydrogen is $+1$
oxidation state of oxygen is $-2$
calculation for P oxidation state is:
$1 × 3 + P + (-2) × 3 = 0$
$3 + P + (-6) = 0$
$3 + P = 6$
$P = 6 - 3$
$= 3$
here oxidation state is $+3.$
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Question 711 Mark
Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.
Answer
Both, nitrogen (N) and chlorine (Cl) have electronegativity of 3.0. However, only
nitrogen is involved in the hydrogen bonds (e.g., NH3) and not chlorine. This is due to smaller atomic size of nitrogen (atomic radius = 70 pm) as compared to chlorine (atomic radius = 99 pm), therefore, N can cause greater polarisation of N-H bond than Cl in case of CI-H bond.Consequently, N atom is involved in hydrogen bonding and not chlorine.
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Question 721 Mark
Why are halogens strong oxidising agents?
Answer
The halogens are strong oxidising agents due to low bond dissociation enthalpy, high electronegativity and large negative electron gain enthalpy.
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Question 731 Mark
Give reasons for the least reactivity of nitrogen molecule.
Answer
Due to presence of a triple bond between the two N-atoms, the bond dissociation enthalpy $(941.4\ kJ\ mol^{-1})$ is very high. Hence, $N_2$​​​​​​​_ is the least reactive.
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Question 741 Mark
Why do boiling points of noble gases increase from helium to radon?
Answer
As the size of the noble gas increases, van der Waals forces of attraction increase accordingly and hence the boiling points increase from He to Rn.
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Question 751 Mark
Can $FCl_3$ exist? Comment.
Answer
No, because F atom has no d-orbital and therefore it cannot expand its valance shell. Further, three big sized Cl atoms cannot be accommodated around a small F atom.
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Question 761 Mark
What are the oxidation states of phosphorus in the following:$Na_3PO_{4}$
Answer
$Na_3PO_{4}$ here oxidation state of sodium is $+1$
oxidation state of oxygen is $-2$
$1 × 3 + P + (-2) × 4 = 0$
$3 + P + (-8) = 0$
$3 + P = 8$
$P = 8 - 3 = 5$
oxidation state is $+5$
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Question 771 Mark
Why is $I_2$ more soluble in KI than in water?
Answer
It is due to formation of soluble complex $KI_3.$
$I_2 + KI → KI_3$
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Question 781 Mark
Elements of Group 16 generally show lower value of first ionisation enthalpy compared to the corresponding periods of Group 15. Why?
Answer
Due to extra stable half-filled p-orbitals electronic configurations of Group 15 elements, larger amount of energy is required to remove electrons compared to Group 16 elements.
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Question 791 Mark
Write balanced equation for the following:
Chlorine gas is passed into a solution of Nal in water.
Answer
when chlorine gas is passed into a solution of Nal it libert iodine.
$2\text{NaI}+\text{Cl}_2\rightarrow2\text{NaCl}+\text{I}_2$
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Question 801 Mark
Why are halogens coloured?
Answer
The halogens are coloured because their molecules absorb light in the visible region. As a result of which their electrons get excited to higher energy levels while the remaining light is transmitted. The color of halogens is the color of this transmitted light.
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Question 811 Mark
Why has it been difficult to study the chemistry of radon?
Answer
It is difficult to study the chemistry of radon because it is a radioactive substance having a half - life of only 3.82 days. Also, compounds of radon such as $RnF_2$ have not been isolated.
They have only been identified.
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Question 821 Mark
Account for the following:
Noble gases have comparatively large atomic sizes.
Answer
Noble gases have only Van der Waals’ radii while others have covalent radii. As van der Waals’ radii are larger than covalent radii, hence, noble gases have comparatively large atomic sizes.
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Question 831 Mark
Give reason for the following:
Helium is used in diving apparatus.
Answer
Helium is used as a diluent for oxygen in modern diving apparatus because of its very low solubility in blood.
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Question 841 Mark
Write balanced equation for the following:
NaCl is heated with sulphuric acid in the presence of $MnO_2.$
Answer
Chlorine gas is produced when NaCl is heated with sulphuric acid in the presenc of $MnO_2$
$2\text{NaCl}+\text{MnO}_2+2\text{H}_2\text{SO}_4\rightarrow\text{Na}_2\text{SO}_4+\text{MnSO}_4+2\text{H}_2\text{O}+\text{Cl}_2\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (\text{conc.})$
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Question 851 Mark
What is the covalence of nitrogen in $N_2O_5?$
Answer

From the structure of $N_2O_5,$ it is evident that the covalence of nitrogen is 4.
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Question 861 Mark
What happens when white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of $CO_2?$
Answer
$\text{P}_4+3\text{NaOH}+3\text{H}_2\text{O}\xrightarrow[\text{CO}_2\text{atm}]{\Delta}\text{PH}_3+\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Phosphine}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3\text{NaHPO}_2\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{sod.hypo-phosphine}$
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Question 871 Mark
Write the order of thermal stability of the hydrides of Group 16 elements.
Answer
The thermal stability of hydrides of group 16 elements decreases down the group.
This is because down the group, size of the element (M) increases, M-H bond length increases and thus,
stability of M-H bond decreases so that it can be broken down easily.
Hence, we have order of thermal stability as
$H_2O > H_2S > H_2Se > H_2Te > H_2PQ.$
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Question 881 Mark
In what way can it be proved that $PH_3$ is basic in nature?
Answer
$PH_3 $ reacts with acids like HI to form $PH_4$ I which shows that it is basic in nature.
$\text{PH}_3+\text{HI}\ \ \ \rightarrow \ \ \text{PH}_4\text{I}$
Due to lone pair of electrons on P atom, $PH_3$ is acting as a Lewis base in the above reaction.
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Question 891 Mark
Why does $NH_3$ form hydrogen bond but $PH_3$ does not?
Answer
Formation of hydrogen bonding depend on the size of molecule. smaller the size greater the hydrogen bonding. Nitrogen has smaller size than phosphrous thus having a more abilty to form hydrogen bond.
N—H bond is reasonably polar and this leads to hydrogen bonding. As the bond polarity of the P—H bond is almost negligible, $PH_3$ is not involved in hydrogen bonding.
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Question 901 Mark
What are the oxidation states of phosphorus in the following:$POF_3$​​​​​​​
Answer
oxidation state fulorine is $(-1)$
oxidation state is $(-2)$
$P + (-2) + (-1) × 3 = 0$
$P = 5$
oxidation state is $+5$
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Question 911 Mark
What are the oxidation states of phosphorus in the following:$Ca_3P_2$​​​​​​​
Answer
oxdation state of calcium is $+2$
$2 × 3 + 2P = 0$
$⇒ 6 + 2P$
$⇒ 2P = -6$
$⇒ P = -6/2 = -3$
oxidation state is $-3$
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Question 921 Mark
Why is $N_2$ less reactive at room temperature?
Answer
Dinitrogen $(N_2)$ is formed by sharing three electron pairs between two nitrogen atoms. The two nitrogen atoms are joined by triple bond $(N≡N).$ The nitrogen atom is very small in size, therefore the bond length is also quite small (109.8 pm) & as a result the bond dissociation energy is quite high (946Kj / mol).This reason leads $N_2​​​​​​​$​​​​​​​ to be very less reactive at room temperature.
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Question 931 Mark
How does xenon atom form compounds with fluorine even though the xenon atom has a closed shell configuration?
Answer
This is because 1, 2 or 3 electrons from the 5p-orbitals can be excited to empty 5d-orbitals and thus making 2, 4 or 6 half-filled orbitals available for bond formation.
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Question 941 Mark
What happens when sulphur dioxide is passed through an aqueous solution of Fe(III) salt?
Answer
$SO_2$ acts as a reducing agent and reduces aqueous solution of Fe (III) salt to Fe (II) salt.
$\text{SO}_2+2\text{H}_2\text{O}\rightarrow\text{SO}_4^{2-}+4\text{H}^++2\text{e}^-\\2\text{Fe}^{3+}+2\text{e}^-\rightarrow2\text{Fe}^{2+}\\\overline{2\text{Fe}^{3+}+\text{SO}_2+2\text{H}_2\text{O}\rightarrow2\text{Fe}^{2+}+\text{SO}_4^{2-}+4\text{H}^+}$
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Question 951 Mark
Balance the following equation:$ XeF_6 + H_2O → XeO_2F_2 + HF$
Answer
$XeF_6 + 2H_2O → XeO_2Fe_2 + 4HF.$
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Question 961 Mark
In which one of the two structures, $\text{NO}^+_2$ and $\text{NO}^-_2$ the bond angle has a higher value?
Answer
$\text{NO}^+_2$ has higher bond angle than $\text{NO}^-_2$ which has a lone pair of electrons on the central atom.
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Question 971 Mark
Arrange the following in the order of property indicated for each set:
$NH_3, PH_3, AsH_3, SbH_3, BiH_3$ – increasing base strength.
Answer
Going from Nitrogen to bismuth size increase as a result electron density decrease hence basicity decrease. In order of increasing base strength.
$NH_3> PH_3> AsH_3> SbH_3> BiH_3$​​​​​​​
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Question 981 Mark
Give the reason for bleaching action of $Cl_2.$
Answer
When chlorine reacts with water, it produces nascent oxygen. This nascent oxygen then combines with the coloured substances present in the organic matter to oxide them into colourless substances.
$\text{Cl}_2+\text{H}_2\text{O}\rightarrow2\text{HCl}+[\text{O}]$
Coloured substances + [O] → Oxidized colourless substance.
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Question 991 Mark
Why does $R_3P = O$ exist but $R_3N = O$ does not (R = alkyl group)?
Answer
$R_3P = 0$ exists but $R_2N = 0$ does not exist because N- due to the absence of d-orbitals cannot form $\text{d}\pi-\text{p}\pi$ multiple bond thus N- cannot expand its covalency beyond the 4.
On other hand P due to having d- oribital forms $\text{d}\pi-\text{p}\pi$ mutiple bonds and hence can expand covalency beyond 4.
thus $R_3P = 0$ exists but $R_2N = 0$ does not exist.
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Question 1001 Mark
Explain why the tendency to show-2 oxidation state diminishes from sulphur to polonium?
Answer
Atomic size increases from sulphur to polonium, therefore, tendency to gain two electrons decreases.
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1 Marks Question - Page 2 - Chemistry STD 12 Science Questions - Vidyadip