Question types

Coordination Compounds question types

343 questions across 6 question groups — pick any mix to generate a Chemistry paper with step-by-step answer keys.

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Sample Questions

Coordination Compounds questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Which of the following metal ion is present in Ziegler$-$Natta catalyst?
  • A
    $ \mathrm{Fe}^{2+} $
  • B
    $ \mathrm{Zr}^{4+} $
  • C
    $ \mathrm{Rh}^{+} $
  • $ \mathrm{Ti}^{4+} $

Answer: D.

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The correct order of ligands for writing the formula of complex compounds is $.......$
  • Neutral, anionic, cationic
  • B
    Anionic, neutral, cationic
  • C
    Anionic, cationic, neutral
  • D
    Cationic, neutral, anionic

Answer: A.

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The two compounds $\left[\mathrm{Co}\left(\mathrm{SO}_4\right)\left(\mathrm{NH}_3\right)_5\right] \mathrm{Br}$ and $\left[\mathrm{Co}\left(\mathrm{SO}_4\right)\left(\mathrm{NH}_3\right)_5\right] \mathrm{Cl}$ represent.
  • A
    Linkage is isomerism
  • B
    Ionisation isomerism
  • C
    Co $−$ ordination isomerism
  • No isomerism

Answer: D.

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The co$-$ordination number of a metal in co$-$ordination compound is:
  • A
    Same as primary valency.
  • B
    Sum of primary and secondary valences.
  • Same as secondary valency.
  • D
    None of the above.

Answer: C.

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$\text{IUPAC}$ name of $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}\left(\mathrm{NO}_2\right)\right]$ is:
  • A
    Platinum diaminechloronitrite.
  • B
    Chloronitrito$-N-$ammineplatinum $(II).$
  • Diamminechloridonitrito$-N-$platinum $(II).$
  • D
    Diamminechloronitrito$-N-$platinate $(II).$

Answer: C.

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Two statements are given$-$ one labelled Assertion $(A)$ and the other labelled Reason $(R).$ Select the correct answer to these questions from the codes $\text{(a), (b), (c)}$ and $(d)$ as given below:
Assertion $(A):\ $ Linkage isomerism arises in coordination compounds because of ambidentate ligand.
Reason $(R):\ $ Ambidentate ligand like $NO_2$ has two different donor atoms i.e., $N$ and $O.$
  • Both Assertion $(A)$ and Reason $(R)$ are correct statements, and Reason $(R)$ is the correct explanation of the Assertion $(A).$
  • B
    Both Assertion $(A)$ and Reason $(R)$ are correct statements, but Reason $(R)$ is not the correct explanation of the Assertion $(A).$
  • C
    Assertion $(A)$ is correct, but Reason $(R)$ is incorrect statement.
  • D
    Assertion $(A)$ is incorrect, but Reason $(R)$ is correct statement.

Answer: A.

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Two statements are given- one labelled Assertion $(A)$ and the other labelled Reason $(R).$ Select the correct answer to these questions from the codes $(a), (b), (c)$ and $(d)$ as given below:
Assertion $(A):$ Linkage isomerism arises in coordination compounds because of ambidentate ligand.
Reason $(R):$ Ambidentate ligand like $NO_2$ has two different donor atoms i.e., $N$ and $O.$
  • Both Assertion $(A)$ and Reason $(R)$ are correct statements, and Reason $(R)$ is the correct explanation of the Assertion $(A).$
  • B
    Both Assertion $(A)$ and Reason $(R)$ are correct statements, but Reason $(R)$ is not the correct explanation of the Assertion $(A).$
  • C
    Assertion $(A)$ is correct, but Reason $(R)$ is incorrect statement.
  • D
    Assertion $(A)$ is incorrect, but Reason $(R)$ is correct statement.

Answer: A.

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In these questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: Ethylenediaminetetraacetate ion forms an octahedral complex with the metal ion
Reason: It has six donor atoms which coordinate simultaneously to the metal ion.
  • Assertion and reason both are correct statements and reason is correct explanation for assertion.
  • B
    Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  • C
    Assertion is correct statement but reason is wrong statement.
  • D
    Assertion is wrong statement but reason is correct statement.

Answer: A.

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In these questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: $\ce{[Cu(NH_3)_4]^{2+}}$ is coloured while $\ce{[Cu(CN)_4]^{3-}}$ ion is colourless.
Reason: $\ce{[Cu(NH_3)_4]^{2+}}$ has $\ce{dsp^2}$ hybridisation.
  • A
    Assertion and reason both are correct statements and reason is correct explanation for assertion.
  • Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  • C
    Assertion is correct statement but reason is wrong statement.
  • D
    Assertion is wrong statement but reason is correct statement.

Answer: B.

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In these questions, a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion: The ligands nitro and nitrito are called ambidentate ligands.
Reason: An ambidentate ligand can attach to metal through two different atoms.
  • Assertion and reason both are correct statements and reason is correct explanation for assertion.
  • B
    Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  • C
    Assertion is correct statement but reason is wrong statement.
  • D
    Assertion is wrong statement but reason is correct statement.

Answer: A.

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Write the IUPAC name of the following coordination compound:
$\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}\left(\mathrm{NH}_2 \mathrm{CH}_3\right)\right] \mathrm{Cl}$
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Specify the oxidation numbers of the metals in the following coordination entities:
$\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right]$
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$\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ is strongly paramagnetic whereas $\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}$ is weakly paramagnetic. Explain.
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Q 163 Marks Question3 Marks
  1. Using valence bond theory, predict the shape and magnetic character of
$[Ni(CO)_4]. [Ni = 28].$
  1. Give one example of application of coordination compounds-in medicine.
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Q 173 Marks Question3 Marks
  1. For the complex $[Fe(H_2O)_6]^{3+},$ write the hybridization, magnetic character and spin of the complex. $($At. number: $Fe = 26)$
  2. Draw one of the geometrical isomers of the complex $[Pt(en)_2Cl_2]^{2+}$ which is optically inactive.
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Q 183 Marks Question3 Marks
  1. What type of isomerism is shown by $[Co(NH_3)_5ONO]Cl_2?$
  2. On the basis of crystal field theory, write the electronic configuration for $d^4$ ion if $\Delta_o < P.$
  3. Write the hybridization and shape of $[Fe(CN)_6]^{_{3-}}.$
$($Atomic number of $Fe = 26)$
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Q 193 Marks Question3 Marks
  1. What type of isomerism is shown by the complex $[Co(NH_3)_5 (SCN)]^{2+}?$
  2. Why is $[NiCl_4]^{2-}$ paramagnetic while $[Ni(CN)_4]^{2-}$ is diamagnetic$? ($Atomic number of $Ni = 28)$
  3. Why are low spin tetrahedral complexes rarely observed?
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Q 203 Marks Question3 Marks
  1. Write the IUPAC name of the complex $[Cr(NH_3)_4 Cl_2]Cl.$
  2. What type of isomerism is exhibited by the complex $[Co(en)_3]^{3+}?$
$($en$=$ ethane$-1,2-$diamine$)$
  1. Why is $[NiCl_4]^{2–}$ paramagnetic but $[Ni(CO)_4]$ is diamagnetic?
$($At. nos.: $Cr= 24, Co=27, Ni= 28)$
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Read the passage given below and answer the following questions:
Coordination compounds are formulated and named according to the IUPAC system.
Few rules for naming coordination compounds are:
  1. In ionic complex, the cation is named first and then the anion.
  2. In the coordination entity, the ligands are named first and then the central metal ion.
  3. When more than one type of ligands are present, they are named in alphabetical order of preference without any consideration of charge.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. The IUPAC name of the complex $[Pt(NH_3)_3Br(NO_2)Cl]Cl$ is:
  1. Triamminechlorobromonitroplatinum (IV) chloride.
  2. Triamminebromonitrochloroplatinum (IV) chloride.
  3. Triamminebromidochloridonitroplatinum (IV) chloride.
  4. Triamminenitrochlorobromoplatinum (IV) chloride.
  1. The IUPAC name of $[Ni(CO)_4]$ is:
  1. Tetracarbonylnickel (II).
  2. Tetracarbonylnickel (0).
  3. Tetracarbonylnickelate (II).
  4. Tetracarbonylnickelate (0).
  1. As per IUPAC nomenclature, the name of the complex $[Co(H_2O)_4(NH_3)_2]Cl_3$ is:
  1. Tetraaquadiamminecobalt (II) chloride.
  2. Tetraaquadiamminecobalt (III) chloride.
  3. Diamminetetraaquacobalt (II) chloride.
  4. Diamminetetraaquacobalt (III) chloride.
  1. Which of the following represents correct formula of dichloridobis(ethane -1, 2-diamine)cobalt (III) ion?
  1. $[CoCl_2(en)]^{2+}$
  2. $[CoCl_2(en)_2]^{2+}$
  3. $[CoCl_2(en)]^+$
  4. $[CoCl_2(en)_2]^+$
  1. Correct formula of pentaamminenitro$-O-$cobalt (III) sulphate is:
  1. $[Co(NO_2)(NH_3)_5]SO_4$
  2. $[Co(ONO)(NH_3)_5]SO_4$
  3. $[Co(NO_2)(NH_3)_4](SO_4)_2$
  4. $[Co(ONO)(NH_3)_4](SO_4)_2$
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Read the passage given below and answer the following questions:
Arrangement of ligands in order of their ability to cause splitting $(\Delta)$ is called spectrochemical series. Ligands which cause large splitting (large $\Delta$) are called strong field ligands while those which cause small splitting (small $\Delta$) are called weak field ligands. When strong field ligands approach metal atom/ ion, the value of $\Delta_0$ is large, so that electrons are forced to get paired up in lower energy $t_{2g}$ orbitals. Hence, a low-spin complex is resulted from strong field ligand. When weak field ligands approach metal atom/ ion, the value of $\Delta_0$ is small, so that electrons enter high energy $e_g$ orbitals rather than pairing in low energy $t_{2g}$ orbitals. Hence, a high-spin complex is resulted from weak field ligands. Strong field ligands have tendency to form inner orbital complexes by forcing the electrons to pair up. Whereas weak field ligands have tendency to form outer orbital complex because inner electrons generally do not pair up.
In these questions (Q. No. i-iv), a statement of assertion followed by a statement ofreason is given. Choose the correct answer out of the following choices.
  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Assertion is wrong statement but reason is correct statement.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. Assertion: In tetrahedral coordination entity formation, the d orbital splitting is inverted and is smaller as compared to the octahedral field splitting.
Reason: Spectrochemical series is based on the absorption of light by complexes with different ligands.
  1. Assertion: In high spin situation, configuration of $d^5$ ions will be $\text{t}^3_{2\text{g}}\text{e}^2_\text{g}.$
Reason: In high spin situation, pairing energy is less than crystal field energy.
  1. Assertion: $F^-$ ion is a weak field ligand and fonns outer orbital complex.
Reason: $F^-$ ion cannot force the electrons of $d_{z^2}$ and $d_{x^2-y^2}$ orbitals of the inner shell to occupy $d_{xy}, d_{yz}$ and $d_{zx}$ orbitals of the same shell.
  1. Assertion: The crystal field model is successful in explaining the formation, structures, colour and magnetic properties of coordination compounds.
Reason: In spectrochemical series, ligands are arranged in a series of increasing field strength.
  1. Assertion: $NF_3$ is a weaker ligand than $N(CH_3)_3$.
Reason: $NF_3$ ionizes to give $F^-$ ions in aqueous solution.
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Read the passage given below and answer the following questions:
Valence bond theory considers the bonding between the metal ion and the ligands as purely covalent. On the other hand, crystal field theory considers the metal-ligand bond to be ionic arising from electrostatic interaction between the metal ion and the ligands. In coordination compounds, the interaction between the ligand and the metal ion causes the five d-orbitals to split-up. This is called crystal field splitting and the energy difference between the two sets of energy level is called crystal field splitting energy. The crystal field splitting energy $(\Delta_0)$ depends upon the nature of the ligand. The actual configuration of complexes is divided by the relative values of $\Delta_0$ and P (pairing energy).
If $\Delta_0<\text{P},$ then complex will be high spin.
If $\Delta_0>\text{P},$ then complex will be low spin
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. Which of the following ligand has lowest $\Delta_0$ value?
  1. $CN^-$
  2. $CO$
  3. $F^-$
  4. $NH_3$
  1. The crystal field splitting energy for octahedral $(\Delta_0)$ and tetrahedral $(\Delta_t)$ complex is related as:
  1. $\Delta_\text{t}=\frac{1}{2}\Delta_0$
  2. $\Delta_\text{t}=\frac{4}{9}\Delta_0$
  3. $\Delta_\text{t}=\frac{3}{5}\Delta_0$
  4. $\Delta_\text{t}=\frac{2}{5}\Delta_0$
  1. On the basis of crystal field theory, the electronic configuration of $d_4$ in two situations : (i) t.0 > P and (ii) t.0
  (i) (ii)
(a) $\text{t}^4_{2\text{g}}\text{e}^0_\text{g}$ $\text{t}^3_{2\text{g}}\text{e}^1_\text{g}$
(b) $\text{t}^3_{2\text{g}}\text{e}^1_\text{g}$ $\text{t}^4_{2\text{g}}\text{e}^0_\text{g}$
(c) $\text{t}^3_{2\text{g}}\text{e}^1_\text{g}$ $\text{t}^3_{2\text{g}}\text{e}^1_\text{g}$
(d) $\text{t}^4_{2\text{g}}\text{e}^0_\text{g}$ $\text{t}^4_{2\text{g}}\text{e}^0_\text{g}$
  1. Using crystal field theory, calculate magnetic moment of central metal ion of $[FeF_6]^{4-}$.
  1. 1.79B.M.
  2. 2.83B.M.
  3. 3.85B.M.
  4. 4.9B.M.
  1. Electronic configuration of d-orbitals in $[Ti(H_2O)_6]^{3+}$​​​​​​​ ion in an octahedral crystal field is:
  1. $\text{t}^1_{2\text{g}}\text{e}^0_\text{g}$
  2. $\text{t}^2_{2\text{g}}\text{e}^0_\text{g}$
  3. $\text{t}^0_{2\text{g}}\text{e}^1_\text{g}$
  4. $\text{t}^1_{2\text{g}}\text{e}^1_\text{g}$
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Read the passage given below and answer the following questions:
To explain bonding in coordination compounds various theories were proposed. One of the important theory was valence bond theory. According to that, the central metal ion in the complex makes available a number of empty orbitals for the formation of coordination bonds with suitable ligands. The appropriate atomic orbitals of the metal hybridise to give a set of equivalent orbitals of definite geometry.
The d-orbitals involved in the hybridisation may be either inner d-orbitals i.e., $(n - 1)d$ or outer d-orbitals i.e., nd. For example, $Co^{3+}$ forms both inner orbital and outer orbital complexes, with ammonia it forms $[Co(NH_3)_6]^{3+}$ and with fluorine it forms $[CoF_6]^{3-}$ complex ion.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. Which of the following is not true for $[CoF_6]^{3-}?$
  1. It is paramagnetic.
  2. It has coordination number of $6.$
  3. It is outer orbital complex.
  4. It involves $d^2sp^3$ hybridisation.
  1. $[Cr(H_2O)_6]Cl_3 ($at. no. of $Cr = 24)$ has a magnetic moment of $3.83B.M.$ The correct distribution of $3d-$electrons in the central metal of the complex is:
  1. $3\text{d}^1_\text{xy},3\text{d}^1_{\text{x}^2-\text{y}^2},3\text{d}^1_\text{yz}$
  2. $3\text{d}^1_\text{xy},3\text{d}^1_{\text{yz}},3\text{d}^1_\text{zx}$
  3. $3\text{d}^1_\text{xy},3\text{d}^1_{\text{zy}},3\text{d}^1_{\text{z}^2}$
  4. $3\text{d}^1_{\text{x}^2-\text{y}^2},3\text{d}^1_{\text{z}^2},3\text{d}^1_\text{xz}$
  1. Which of the following is true for $[Co(NH_3)_6]^{3+}?$
  1. It is an octahedral, di magnetic and outer orbital complex.
  2. It is an octahedral, paramagnetic and outer orbital complex.
  3. It is an octahedral, paramagnetic and inner orbital complex.
  4. It is an octahedral, di magnetic and inner orbital complex.
  1. The paramagnetism of $[CoF_6]^{3-}$ is due to.
  1. $3$ electrons.
  2. $4$ electrons.
  3. $2$ electrons.
  4. $1$ electron.
  1. Which of the following is an inner orbital or low spin complex?
  1. $[Ni(H_2O)_6]^{3+}$
  2. $[FeF_6]^{3-}$
  3. $[Co(CN)_6]^{3-}$
  4. $[NiCl_4]^{2-}$
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Read the passage given below and answer the following questions:
Werner, a Swiss chemist in $1892$ prepared and characterised a large number of coordination compounds and studied their physical and chemical behaviour. He proposed that, in coordination compounds, metals possess two types of valencies, viz. primary valencies, which are normally ionisable and secondary valencies which are non-ionisable. ln a series of compounds of cobalt (III) chloride with ammonia, it was found that some of the chloride ions could be precipitated as $AgCl$ on adding excess of $AgNO_3$ solution in cold, but some remained in solution. The number ofions furnished by a complex in a solution can be determined by precipitation reactions. The measurement of molar conductance of solutions of coordination compounds helps to estimate the number of ions furnished by the compound in solution.
In these questions (Q. No. i-iv), a statement of assertion followed by a statement ofreason is given. Choose the correct answer out of the following choices.
  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
  3. Assertion is correct statement but reason is wrong statement.
  4. Assertion is wrong statement but reason is correct statement.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. Assertion: The complex $[Co(NH_3)_3Cl_3]$ does not give precipitate with silver nitrate solution.
Reason: The given complex is non-ionisable.
  1. Assertion: The complex $[Co(NH_3)_4Cl_2]Cl$ gives precipitate corresponding to 2 mol of AgCl with $AgNO_3$ solution.
Reason: It ionises as $[Co(NH_3)_4Cl_2]^+ + Cl^-.$
  1. Assertion: $CoCl_3. 4NH_3$ gives 1 mol of AgCl on reacting with $AgNO_3$​​​​​​​, its secondary valency is 6.
Reason: Secondary valency corresponds to coordination number.
  1. Assertion: 1 mol of $[CrCl_2(H_2O)_4]Cl· 2H_2O$ will give 1 mol of AgCl on treating with $AgNO_3$​​​​​​​.
Reason: $Cl^-$ ions satisfying secondary valanceis will not be precipitated.
  1. Assertion: $CoCl_3. 3NH_3$ is not conducting while $CoCl_3. 5NH_3$​​​​​​​ is conducting.
Reason: The complex of $CoCl_3. 3NH_3$ is $[CoCl_3(NH_3)_3]$ while that of $CoCl_3· 5NH_3$ is $[CoCl(NH_3)_5]Cl_3$.
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$\mathrm{CoSO}_4 \mathrm{Cl} .5 \mathrm{NH}_3$ exists in two isomeric forms ' A ' and ' B '. Isomer ' A ' reacts with $\mathrm{AgNO}_3$ to give white precipitate, but does not react with $\mathrm{BaCl}_2$. Isomer 'B' gives white precipitate with $\mathrm{BaCl}_2$ but does not react with $\mathrm{AgNO}_3$. Answer the following questions.
  1. Identify ‘A’ and ‘B’ and write their structural formulas.
  2. Name the type of isomerism involved.
  3. Give the IUPAC name of ‘A’ and ‘B’.
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Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:
 
Column I (Complex ion)
 
Column II (Hybridisation, number of unpaired electrons)
$a.$
$[Cr(H_2O)_6]^{3+}$
$1.$
$dsp^2, 1$
$b.$
$[Co(CN)_4]^{2-}$
$2.$
$sp^3d^2, 5$
$c.$
$[Ni(NH_3)_6]^{2+}$
$3.$
$d^2sp^3, 3$
$d.$
$[MnF_6]^{4-}$
$4.$
$sp^3, 4$
 
 
$5.$
$sp^3d^2, 2$
Code:
  1. $A (3), B (1), C (5), D (2).$
  2. $A (4), B (3), C (2), D (1).$
  3. $A (3), B (2), C (4), D (1).$
  4. $A (4), B (1), C (2), D (3).$
View full solution
Give the electronic configuration of the following complexes on the basis of Crystal Field Splitting theory. $[CoF_6]^{3-}, [Fe(CN)_6]^{4-}$ and $[Cu(NH_3)_6]^{2+}​​​​​​​$​​​​​​​
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Match the complex ions given in Column I with the colours given in Column II and assign the correct code:
 
Column I (Complex ion)
 
Column II (Colour)
$a.$
$[Co(NH_3)_6]^{3+}$
$1.$
Violet
$b.$
$[Ti(H_2O)_6]^{3+}$
$2.$
Green
$c.$
$[Ni(H_2O)_6]^{2+}$
$3.$
Pale blue
$d.$
$[Ni(H_2O)_4(en)]^{2+} (aq)$
$4.$
Yellowish orange
 
 
$5.$
Blue
Code:
  1. $A (1), B (2), C (4), D (5).$
  2. $A (4), B (3), C (2), D (1).$
  3. $A (3), B (2), C (4), D (1).$
  4. $A (4), B (1), C (2), D (3).$
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