Question types

Periodic Classification of Elements question types

193 questions across 8 question groups — pick any mix to generate a Science paper with step-by-step answer keys.

193
Questions
8
Question groups
5
Question types
Sample Questions

Periodic Classification of Elements questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Assertion (A): Electroplating method not only protects but also enhances the metallic appearance.
Reason (R): Electroplating is a method of coating one metal with another by passing current.
  • A
    (A) is right, (R) is wrong
  • B
    (A) is right, (R) is not relevant
  • (A) is right, (R) is relevant
  • D
    Both (A) and (R) are wrong.

Answer: C.

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Assertion (A): Magnesium is used in a sacrificial protection method to prevent corrosion.
Reason (R): Magnesium is more reactive than iron. When it is coated on the articles made of steel, it sacrifices itself to protect steel.
  • Both (A) and (R) are correct
  • B
    Both (A) and (R) are not correct
  • C
    (A) is correct but (R) is wrong
  • D
    (A) is wrong but (R) is correct.

Answer: A.

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Assertion (A): Nickel steel is used in making cables, aircraft parts and propeller.
Reason (R): Nickel steel alloy is hard, brittle and polishable.
  • A
    Both (A) and (R) are correct
  • B
    Both (A) and (R) are not correct
  • (A) is correct but (R) is wrong
  • D
    (A) is wrong but (R) is correct.

Answer: C.

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Assertion (A): Duralumin is used in making aircraft, tools and pressure cookers.
Reason (R): Duralumin is an alloy that is light, strong, resistant to corrosion.
  • Both (A) and (R) are correct
  • B
    Both (A) and (R) are not correct
  • C
    (A) is correct but (R) is wrong
  • D
    (A) is wrong but (R) is correct.

Answer: A.

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Assertion (A): When iron is dipped in conc. $HNO _3$ it becomes chemically inert (or) passive.
Reason (R): Iron becomes passive when treated with nitric acid is due to the formation of a layer of iron oxide $Fe _3 O _4$ on its surface.
  • A
    Both (A) and (R) are correct
  • B
    (A) is correct but (R) is wrong
  • C
    (A) is wrong but (R) is correct
  • Both (A) and (R) are wrong.

Answer: D.

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Metal A belongs to period 4 and group 8. A in red hot condition reacts with steam to form B. A reacts with dilute HNO3 to give C. A again reacts with conc. H2SO4 to give D. Find A, B, C and D with suitable reaction.
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A silvery - white metal on treatment with NaOH and HCl liberates H 2 gas to form B and C respectively. The metal A will not react with acid D due to the formation of a passive film on the surface. Hence it is used for transporting acid D. Identify A, B, C, D and support your answer with balanced equations.
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A reddish – brown metal A, when exposed to moist air, forms a green layer B. When A is heated at different temperatures in the presence of O2, it forms two types of oxides – C (black) and D (red). Identify A, B, C, D and write the balanced equation.
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Metal Ore Chemical formula
1. Copper Bauxite $ZnCO _3$
2. Aluminium Haematite $CuFeS _2$
3. Iron Copper pyrite $Fe _2 O _3$
4. Zinc Calamine $Al _2 O _3 \cdot 2 H _2 O$
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AlloyMetals presentUses
1. BrassFe, C, NiStatues, Coins
2. BronzeAl, Mg, Mn, CuAircraft, Pressure cookers
3. DuraluminFe, C, Ni, CrCables, Propeller
4. MagnaliumCu, SnAutomobile parts, Utensils
5. Stainless steelCu, ZnScientific instruments, Air craft
6. Nickel steelAl, MgMedals, decorative items
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Process Ores
i. Hydraulic process (a) $ZnS$
ii. Magnetic separation (b) $Fe _2 O _3$
iii. Froth floatation process (c) $SnO _2$
iv. Leaching process (d) $Al _2 O _3 \cdot 2 H _2 O$
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