A person standing near the edge of the top of a building throws two balls $A$ and $B.$ The ball $A$ is thrown vertically upward and $B$ is thrown vertically downward with the same speed. The ball $A$ hits the ground with a speed $v_A$ and the ball $B$ hits the ground with a speed $v_B$. We have:
- A$\mathrm{v}_{\mathrm{A}}>\mathrm{v}_{\mathrm{B}}$
- B$v_A<v_B$
- ✓$v_A=v_B$
- DThe relation between $v_A$ and $v_B$ depends on height of the building above the ground.
Answer: C.
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