mass of solute \((w)\,=\,120\,g\)

mass of solvent \((w)\,=\,1000\,g\)

Mol. mass of solute \(=60\,g\)

density of solution \(=\,1.12\,g/ml\)

From the given data,

Mass of solution \(=\,1000+120=1120\,g\)

\(d=\frac {Mol.mass}{V}\) or \(V=\frac {Mol.mass}{d}\)

Volume of solution \(V\,=\,\frac {1120}{1.12}\,=\,1000\,ml\) or

\(=\,1\,litre\)

Now molarity \((M)\) \(=\,\frac {W}{Mol.\,mass\times V(lit)}\) \(=\,\frac {120}{60\times 1}\) \(=\,2\,M\)