$K_{sp} = 4S^3$ અને $2S = 1.5 \times 10^{-4}$ હોવાથી
$\therefore \,{K_{sp}} = {(2S)^2} \times S\,\, = {(1.5 \times {10^{ - 4}})^2} \times \left( {\frac{{1.5 \times {{10}^{ - 4}}}}{2}} \right)\,\,\, = 1.6875 \times {10^{ - 12}}$
$[K_{sp}\, BaSO_4 = 10^{-11}, K_{sp}\, CaSO_4 = 10^{-6}, K_{sp}\,Ag_2SO_4 = 10^{-5}]$