Position of object \(u=-50\,cm\)
Power gets added
\(P=P_1+P_2\)
\(P=3-5=-2\)
\(f=\frac{1}{P}=\frac{1}{-2}=-50\,cm\)
Apply lens formula
\(\frac{1}{ f }=\frac{1}{ v }-\frac{1}{ u }\)
\(v =\frac{ uf }{ f + u }=\frac{(-50) \times(-50)}{(-50)+(-50)}=+25\,cm\)
Position of image is \(V =+25\,cm\)