Now \(T E=\frac{1}{2} mv ^{2}+\left(\frac{- GMm }{ r }\right)\)
but \(\frac{ mv ^{2}}{ r }=\frac{ GMm }{ r ^{2}} \Rightarrow mv ^{2}=\frac{ GMm }{ r }\)
\(\Rightarrow TE =-\frac{ GMm }{2 r } \propto \frac{ m }{ r }\)
\(\frac{T E_{1}}{T_{2}}=\frac{m_{1}}{m_{2}} \cdot \frac{r_{2}}{r_{1}}=\frac{4}{3} \times \frac{4}{3}=\frac{16}{9}\)