Given : $T _{ f }^{\circ}=5.5^{\circ} C$
$K _{ f }=5.12^{\circ}\,C / m$
$\because \Delta T _{ f }= k _{ f } \times m$
$\Rightarrow\left( T _{ f }^{0}- T _{ f }^{\prime}\right)=5.12 \times \frac{\left(\frac{10}{58}\right)}{\left(\frac{200}{1000}\right) \,kg } \,mol$
$\Rightarrow 5.5- T _{ f }^{\prime}=\frac{5.12 \times 5 \times 10}{58}$
$\Rightarrow T _{ f }^{\prime}=1.086^{\circ} C \simeq 1^{\circ} C$
[ આપેલ : પાણીનો મોલલ ઉત્કલનબિંદુ ઉન્નયન અચળાંક $\left(\mathrm{K}_{\mathrm{b}}\right)=0.52 \mathrm{~K} . \mathrm{kg} \mathrm{mol}^{-1}$,
$1 \mathrm{~atm}$ દબાણ $=760 \mathrm{~mm} \mathrm{Hg}$, પાણીનું મોલર દળ $\left.=18 \mathrm{~g} \mathrm{~mol}^{-1}\right]$