A Carnot engine absorbs an amount $Q$ of heat from a reservoir at an absolute temperature $T$ and rejects heat to a sink at a temperature of $T/3$ . The amount of heat rejected is
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$\because \eta=1-\frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}=\frac{\mathrm{W}}{\mathrm{Q}_{1}}$

where $Q_{1}=$ heat absorbed, $Q_{2}=$ heat rejected

$\Rightarrow 1-\frac{\mathrm{T} / 3}{\mathrm{T}}=\frac{\mathrm{W}}{\mathrm{Q}_{1}} \Rightarrow \frac{2}{3}=\frac{\mathrm{W}}{\mathrm{Q}_{1}}=\frac{\mathrm{Q}_{1}-\mathrm{Q}_{2}}{\mathrm{Q}_{1}}$

$\Rightarrow \frac{2}{3}=1-\frac{Q_{2}}{Q_{1}} \Rightarrow \frac{Q_{2}}{Q_{1}}=\frac{1}{3} \Rightarrow Q_{2}=\frac{Q_{1}}{3}=\frac{Q}{3}$

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