A Carnot engine operates between two reservoirs of temperatures $900\; \mathrm{K}$ and $300 \;\mathrm{K}$ The engine performs $1200\; \mathrm{J}$ of work per cycle. The heat energy (in $\mathrm{J}$ ) delivered by the engine to the low temperature reservoir, in a cycle. is
JEE MAIN 2020, Medium
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$\frac{Q_{1}}{Q_{2}}=\frac{T_{1}}{T_{2}}$
$\frac{\mathrm{Q}+1200}{\mathrm{Q}}=\frac{900}{300}$
$\mathrm{Q}+1200=3 \mathrm{Q}$
$Q=600 \mathrm{J}$
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