A Carnot's heat engine works between the temperatures $427^{\circ} C$ and $27^{\circ} C$. $...........\,kcal / s$ amount of heat should it consume per second to deliver mechanical work at the rate of $1.0\,kW$
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(a)
The efficiency of the heat engine is
$\eta=1-\frac{T_2}{T_1}=1-\left(\frac{273+27 K}{273+427 K}\right)=\frac{4}{7}$
But $\eta=\frac{ W }{ Q _1}$
$\therefore Q _1=\frac{ W }{\eta}=\frac{1.0 kW }{4 / 7}=1.75 kW =0.417 kcal / s$
Thus, the engine would require $417 cal$ of heat per second, to deliver the requisite amount of work.
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