A charge particle moving in magnetic field $B$, has the components of velocity along $B$ as well as perpendicular to $B$. The path of the charge particle will be
JEE MAIN 2023, Medium
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Due to component $v_1$,
magnetic force $F = qv _1 B \sin \theta=0$
So $v _1$ remains unchanged
but due to component $v_2$ magnetic force act towards centre i.e. moving it circular. So path is helical with the axis parallel to magnetic field $B$.
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