$R = 8.314\, J\,K^{-1}\,mol^{-1} \,\,\,2.303 \times 8.314 \times 298 = 5705$
$\Delta G° = -54.07×103 - 298 × 10 = - 57050 $ અને
$\Delta G° = -2.303 RT$ $log_{10}K$
$- 57050 = -2.303 × 8.314 × 298 × log_{10}K$
$log_{10}K = 10$
આપેલ : $\Delta H _{ f }{ }^\theta\left( Al _2 O _3\right)=-1700\,kJ\,mol ^{-1}$
$\Delta H _{ f }{ }^\theta\left( Fe _2 O _3\right)=-840\,kJ\,mol ^{-1}$
$Fe , Al$ અને $O$ નું મોલર દળ અનુક્રમે $56,27$ અને $16\,g\,mol ^{-1}$.