A sphere of $4\, cm$ radius is suspended within a hollow sphere of $6\, cm$ radius. The inner sphere is charged to potential $3\, e.s.u.$ and the outer sphere is earthed. The charge on the inner sphere is.....$e.s.u.$
A$54$
B$0.25$
C$30$
D$36$
Diffcult
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D$36$
d (d) Suppose charge on inner sphere is $+Q$ as shown.
Potential on inner sphere
$V = \frac{Q}{4} - \frac{Q}{6}$
$==>$ $3 = Q\,\left( {\frac{1}{4} - \frac{1}{6}} \right)$ $==>$ $Q = 36\,e.s.u.$
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