A voltage of 30V is applied across a carbon resistor with first, second and third rings of blue, black and yellow colours respectively. Calculate the value of current in mA, through the resistor.
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Value of first digit (blue ring) = 6
Value of second digit (black ring) = 0
Multiplier (yellow ring) = 104
$\therefore$ Resistance, $\text{R} = 60 \times104\Omega, $ Voltage, V = 30V
Current $\text{I}=\frac{\text{V}}{\text{R}}=\frac{30}{60\times10^4}=0.5\times10^{-4}\text{A}=0.05\text{mA.}$
Value of second digit (black ring) = 0
Multiplier (yellow ring) = 104
$\therefore$ Resistance, $\text{R} = 60 \times104\Omega, $ Voltage, V = 30V
Current $\text{I}=\frac{\text{V}}{\text{R}}=\frac{30}{60\times10^4}=0.5\times10^{-4}\text{A}=0.05\text{mA.}$
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