Cap. is fully charged
So no current is there in branch \(ADB\)
Effective circuit of current flow
\(R_{e q}=\left(\frac{4 \times 2}{4+2}\right)+2\)
\(R _{ eq }=\frac{4}{3}+2=\frac{10}{3} \Omega\)
\(i=\frac{10}{10 / 3}=3 A\)
So potential different across \(AEB\)
\(\Rightarrow 2 \times 1+2 \times 3=8 V\)
Hence potential difference across
Capacitor \(=\Delta V = V _{ AEB }=8 V\)