$(K_f =-1.86\,^o\, C/m)$
\(i=\frac{\Delta T_{f}}{k_{f} \cdot m}\)
\(=\frac{0.00732}{1.86 \times 0.002}=\frac{0.00732}{0.00372}\)
\(i=2\)
Compound will be \(\left.\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\right] \mathrm{NO}_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}\)
Total possible ions \(=2\)