$\begin{array}{llll} t =0  a  0  0\end{array}$

$\begin{array}{llll} t = t  a - a \alpha  a \alpha  2 a \alpha\end{array}$

$n _{ T }= a - a \alpha+ a \alpha+2 a \alpha$

$= a (1+2 \alpha)$

so $i =1+2 \alpha$

Now $\Delta T _{ b }= i \times m \times K _{ b }$

$\Delta T _{ b }=(1+2 \alpha) \times m \times K _{ b }$

$\alpha=0.1 \quad m =10 \quad K _{ b }=0.5$

$\Delta T _{ b }=1.2 \times 10 \times 0.5$

$=6$

So boiling point $=106$