An open glass tube is immersed in mercury in such a way that a length of $8\ cm$ extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional $46\ cm$. What will be length of the air column above mercury in the tube now ....... $cm$ ?
( Atmospheric pressure = $76\ cm$ of $Hg$)
JEE MAIN 2014, Medium
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Length of the air column above mercury in the tube is,
$p + x = {P_0}$
$ \Rightarrow p = \left( {76 - x} \right)$
$ \Rightarrow 8 \times A \times 76 = \left( {76 - x} \right) \times A \times \left( {54 - x} \right)$
$\therefore \,x = 38$
Thus, lenght of air column $=54-38=16\,cm.$
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