MCQ
Assertion : Equivalent weight of a base $= \frac{Molecular\, weight}{Acidity}$
Reason : Acidity is the number of replaceable hydrogen atoms in one molecule of the base.
  • A
    If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
  • B
    If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
  • If the Assertion is correct but Reason is incorrect.
  • D
    If both the Assertion and Reason are incorrect.

Answer

Correct option: C.
If the Assertion is correct but Reason is incorrect.
c
Yes, $Eq. wt$ of a base $= \frac{Molecular \,weight}{Acidity}$ Thus, assertion is correct. Acidity is the number of replacable $-OH$ groups (not hydrogen atoms) present in a molecule . Thus, reason is false.

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Iso-electronic species is
The wave function $\psi_{n / m m}$ is a mathematical function whose value depends upon spherical polar coordinates $(r, \theta, \phi)$ of the electron and characterized by the quantum numbers $n, l$ and $m_l$. Here $r$ is distance from nucleus, $\theta$ is colatitude and $\phi$ is azimuth. In the mathematical functions given in the Table, $\mathrm{Z}$ is atomic number and $a_0$ is Bohr radius.

$column 1$ $column 2$ $column 3$
$(I)$ $1$s orbital $(i)$ $\psi_{n, l, m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{3}{2}} e^{-\left(\frac{Z r}{a_0}\right)}$ $image$
($II$) $2 \mathrm{~s}$ orbital $(ii)$ One radial node $(Q)$ Probability density at nucleus $\propto \frac{1}{a_0^3}$
$(III)$ $2 p_z$ orbital $(iii)$ $\psi_{n, l m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{5}{2}} r e^{-\left(\frac{Z r}{2 a_0}\right)} \cos \theta$ $(R)$ Probability density is maximum at nucleus
$(IV)$ $3 \mathrm{~d}_{\mathrm{z}}^2$ orbital $(iv)$ $x y$-plane is a nodal plane $(S)$ Energy needed to excite electron from $n=2$ state to $n=4$ state is $\frac{27}{32}$ times the energy needed to excite electron from $n=2$ state to $n=6$ state

($1$) For the given orbital in Column $1$, the only $CORRECT$ combination for any hydrogen-like species is

$[A] (IV) (iv) (R)$   $[B] (II) (ii) (P)$    $[C] (III) (iii) (P)$    $[D] (I) (ii) (S)$

($2$)  For $\mathrm{He}^{+}$ion, the only INCORRECT combination is

$[A] (II) (ii) (Q)$ $[B] (I) (i) (S)$ $[C] (I) (i) (R)$ $[D] (I) (iii) (R)$

($3$) For hydrogen atom, the only $CORRECT$ combination is

$[A] (I) (iv) (R)$   $[B] (I) (i) (P)$    $[C] (II) (i) (Q)$   $[D] (I) (i) (S)$

Give the answer quetion ($1$) ($2$) and ($3$)

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