At what distance on the axis, from the centre of a circular current carrying coil of radius $r$, the magnetic field becomes $1 / 8$ th of the magnetic field at centre?
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(c)

$\frac{1}{8} \frac{\mu_0 i}{2 r}=\frac{\mu_0 / r^2}{2\left(r^2+x^2\right)^{3 / 2}}$

$\Rightarrow\left(r^2+x^2\right)^{3 / 2}=8 r^3$

$\Rightarrow\left(r^2+x^2\right)=\left(8 r^3\right)^{2 / 3}$

$\Rightarrow r^2+x^2=4 r^2$

$\Rightarrow 3 r^2=x^2$

$\Rightarrow x=r \sqrt{3}$

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