$0.8=1-\frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}$
$\frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}=0.2$
$\mathrm{T}_{2} \mathrm{V}_{2}^{\gamma-1}=\mathrm{T}_{1} \mathrm{V}_{1}^{\gamma-1}$
$\left(\frac{\mathrm{V}_{2}}{\mathrm{V}_{1}}\right)^{\gamma-1}=\frac{\mathrm{T}_{1}}{\mathrm{T}_{2}}=5$
$\frac{V_{1}}{V_{2}}=\left(\frac{1}{5}\right)^{\frac{5}{2}}$



| Column $I$ | Column $II$ |
| $(p)$ isobaric | $(x)$ $\frac{{PV(1 - {2^{1 - \gamma }})}}{{\gamma - 1}}$ |
| $(q)$ isothermal | $(y)$ $PV$ |
| $(r)$ adiabatic | (z) $PV\,\iota n\,2$ |
The correct matching of column $I$ and column $II$ is given by

