1. Draw a ray diagram showing the image formation by a compound microscope. Hence obtain expression for total magnification when the image is formed at infinity.
  2. Distinguish between myopia and hypermetropia. Show diagrammatically how these defects can be corrected.
CBSE DELHI - SET 1 2013
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  1. Difference between myopia and hypermetropia
Myopia Hypermetropia
  1. The eye ball is elongated.
  1. The eye ball is shortened.
  1. Person cannot see distant objects clearly.
  1. Person cannot see near objects clearly.
  • Myopic eye is corrected by interposing a concave lens between eye and object.
  • Hypermetropia is corrected by interposing a convex lens between eye and object.
  1. If image A 'B' is exactly at the focus of the eyepiece, then image A "B" is formed at infinity. If the object AB is very close to the focus of the objective lens of focal length $f_o$, then magnification $M_o$ by the objective lens
$\text{M}_{e} = \frac{\text{L}}{\text{f}_{o}}$
where L is tube length (or distance between lenses $L_o$ and $L_e$)
Magnification $M_e$ by the eyepiece
$\text{M}_{e} = \frac{\text{D}}{\text{f}_{e}}$
where D = Least distance of distinct vision Total magnification $m = M_oM_e$​​​​​​​
$ = \bigg(\frac{\text{L}}{\text{f}_{o}}\bigg)\bigg(\frac{\text{D}}{\text{f}_{e}}\bigg).$
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