Therefore, negative work is done by ice-water system on the atmosphere or positive work is done on the ice-water system by the atmosphere.
Hence option $(b)$ is correct. Secondly heat is absorbed during melting (i.e.$\Delta Q$ is positive) and as we have seen, work done by ice-water system is negative ($\Delta W$ is negative).
Therefore, from first law of thermodynamics $\Delta U = \Delta Q - \Delta W.$
Change in internal energy of ice-water system, $\Delta U$ will be positive or internal energy will increase.



Let $\Delta v=X$ cc and $\Delta p=Y \times 10^3 Pa$.
($1$) The value of $X$ is
($2$) The value of $Y$ is
Give the answer or quetion ($1$) and ($2$)
