$=\frac{12}{44} \times \frac{\text { mass of } CO _2 \text { formed }}{\text { mass of compound taken }} \times 100$

$60=\frac{12}{44} \times \frac{\text { mass of } CO _2 \text { formed }}{0.5} \times 100$

Mass of $CO _2$ formed $=\frac{60 \times 44 \times 0.5}{12 \times 100}\,g$

$=1.1 \text { gram }$

$=11 \times 10^{-1} \text { gram }$