a
When capacitance is taken out, the circuit is \(LR.\)

\(\therefore \tan \phi=\frac{\omega L}{R}\)

\(\Rightarrow \omega L=R \tan \phi=200 \times \frac{1}{\sqrt{3}}=\frac{200}{\sqrt{3}}\)

Again, when inductor is taken out, the circuit is \(CR\)

\(\tan \phi=\frac{1}{\omega C R}\)

\(\frac{1}{\omega c}=R \tan \phi=200 \times \frac{1}{\sqrt{3}}=\frac{200}{\sqrt{3}}\)

Now, \(Z=\sqrt{R^{2}+\left(\frac{1}{\omega C}-\omega L\right)^{2}}\)

\(=\sqrt{(200)^{2}+\left(\frac{200}{\sqrt{3}}-\frac{200}{\sqrt{3}}\right)^{2}}=200\, \Omega\)

Power dissipated \(=V_{r m s} I_{r m s} \cos \phi\)

\(=V_{\mathrm{rms}} \cdot \frac{V_{\mathrm{rms}}}{Z} \cdot \frac{R}{Z}\left(\because \cos \phi=\frac{R}{Z}\right)\)

\(=\frac{V^{2} \operatorname{ms} R}{Z^{2}}=\frac{(220)^{2} \times 200}{(200)^{2}}=\frac{220 \times 220}{200}=242 \,\mathrm{W}\)