Where, $\Lambda^{o}$ and $\Lambda^{\infty}$ are equivalent conductances at a given concentration and at infinite dilution respectively. $\alpha=\frac{8.0}{400}=2 \times 10^{-2}$
From Ostwald's dilution law (for weak monobasic acid)
$\mathrm{K}_{\mathrm{a}}=\frac{\mathrm{C} \alpha^{2}}{(1-\alpha)}$
$=\mathrm{C} \alpha^{2} \quad(\because 1>>\alpha)$
$=\frac{1}{32}\left(2 \times 10^{-2}\right)^{2}$
$=1.25 \times 10^{-5}$
આપેલ $: \frac{2.303 RT }{ F }=0.06 V$
$Pd _{( aq )}^{2+}+2 e ^{-} \rightleftharpoons Pd ( s ) \quad E ^{\circ}=0.83\,V$
$PdCl _4^{2-}( aq )+2 e ^{-} \rightleftharpoons Pd ( s )+4 Cl ^{-}( aq )$
$E ^{\circ}=0.65\,V$
$298\,K$ પર જ્યારે $\frac{\left[M^*(a q)\right]}{\left[M^{3 *}(a q)\right]}=10^a$ હોય ત્યારે આપેલ કોષ નો $E_{\text {cell }}$ એ $0.1115\,V$ છે. $a$ નું મૂલ્ય $............$ છે.આપેલ : $E _{ M }^\theta{ }^{3+} M ^{+}=0.2\,V$
$\frac{2.303\,R T}{F}=0.059\,V$