$\frac{\Delta T _{ b }}{\Delta T _{ f }}=\frac{ K _{ b } \times 1}{ K _{ f } \times 2}$ $\Rightarrow \frac{3}{6}=\frac{1}{2}=\frac{ K _{ b }}{ K _{ f }} \times \frac{1}{2}$
$\frac{ K _{ b }}{ K _{ f }}=\frac{1}{1} \Rightarrow x =1$
(પાણી માટે $K_f = 1.86\,^oC\, kg\, mol^{-1}$ છે)
(મોલર દળ $S = 32\, g\, mol^{-1}, Na = 23\, g\, mol^{-1}$ )
[આપેલ : એસિટિક એસિડની ધનતા $1.02\,g\,mL ^{-1}$ છે.એસિટિક એસિડનું મોલર દળ $60\,g\,mol ^{-1}$ છે.$\left. K _{f}\left( H _{2} O \right)=1.85 K\,kg\,mol ^{-1}, K _{f}\left( H _{2} O \right)=1.85\,K\,kg\,mol ^{-1}\right]$