For an ideal heat engine, the temperature of the source is $127\,^{\circ} C$. In order to have $60\, \%$ efficiency the temperature of the sink should be $........\,{ }^{\circ} C$. (Round off to the Nearest Integer)
JEE MAIN 2021, Medium
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$n =0.60=1=\frac{ T _{ L }}{ T _{ H }}$
$\frac{ T _{ L }}{ T _{ H }}=0.4 \Rightarrow T _{ L }=0.4 \times 400$
$=160\, K$
$=-113\,^{\circ} C$
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