It is safer to jump from a height of \(3 \,m\) on earth,

\(\Rightarrow\) Corresponding velocity attained \(=\sqrt{2 g_1 h_1}\)

It will be safer to jump from a height on other planet

If the velocity attained is same \(=\sqrt{2 g_2 h_2}\)

\(\Rightarrow \sqrt{2 g_1 h_1}=\sqrt{2 g_2 h_2}\)

\(9.8 \times 3=1.96 \times h_2\)

\(\Rightarrow h_2=5 \times 3=15 \,m\)